7a+4-6a^2-2a=a

Solution for 7a+4-6a^2-2a=a equation:

7a+4-6a^2-2a=a

We move all terms to the left:

7a+4-6a^2-2a-(a)=0

We add all the numbers together, and all the variables

-6a^2+4a+4=0

a = -6; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·(-6)·4
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{7}}{2*-6}=\frac{-4-4\sqrt{7}}{-12}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{7}}{2*-6}=\frac{-4+4\sqrt{7}}{-12}
$